A 0.087 kg bullet is fired and will soon collide with a 3.2 kg wooden block. The bullet has not collided with the block yet. At this time, the bullet and block system can be described as follows:
Vbullet = 225 m/s
Vwood block = 0 m/s
What is the total momentum of the system at this time?
Answers: 3
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A 0.087 kg bullet is fired and will soon collide with a 3.2 kg wooden block. The bullet has not coll...
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