WILL GIVE BRAINLIEST The truck had kinetic energy of 72 MJ and came to a stop in 5 metres. Calculate the force exerted by the brakes showing all working

The force exerted by the brakes is 14,400,000 N

Explanation:

Initial kinetic energy of truck = 72 MJ

Work done by the breaks, W = Force exerted by the brakes × Distance, D, the truck came to stop

The distance, D, in which the truck came to a stop is given as 5 meters

Given that the initial kinetic energy, KE of the truck  that was reduced by the breaks = The work done by the brakes

We have;

W = ΔKE = Change in kinetic energy

ΔKE = Initial kinetic energy - Final Kinetic Energy

Initial kinetic energy, KE = 72 MJ

Final Kinetic Energy = 0 J (Truck stopped)

ΔKE = 72 - 0 = 72 MJ

Therefore we have;

Force exerted by the breaks = W/D = 72 MJ/5 = 14.4 MN. = 14,400,000 N.

unbalanced force

explanation:

it has to be b, about 97 percent.