Ahorizontal rope is tied to a 50.0kg box on frictionless ice.
what is the tension in the rope if,
a. the box is at rest
b. the box moves at a steady 5.0m/s
c. the box has v_x=5.0m/s and a_x=5.0m/s^2

a) 0

b) 0

c) 250 N

Explanation:

A) When the box is at rest, it has zero acceleration, consequenly, the net force acting on the box is zero, and the rope has no tension. Tension = 0.

B) When the box is moving at a setady 5.0 m/s, again it has zero acceleration. So the same explanation above applies: net force = 0, and tension = 0.

C) When the box has Vx = 5.0 m/s and Ax = 5.0 m/s², you use the second law of Newton to find the net force:

F = mass × acceleration = 50 kg × 5 m/s² = 250 N

Since the box is on frictionless ice, there is not friction force, and the tension is equal to the net force. Tension = 250 N.

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i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.