3) A lead sinker of mass 225 grams and density of 11.3 g/cm3 is attached to the bottom of a wooden block of mass 25 grams and density 0.5 g/cm3. Calculate the apparent weight when both are submerged in water.

180.1 g

Explanation:

Data provided in the question

Mass of lead sinker = 225 grams

Density = 11.3 g/cm^3

The Wooden block of mass = 25 grams

Density = 0.5/g cm^3

Based on the above information, the apparent weight is

Before that we need to do the following calculations

= 19.91 cm^3

= 50 cm^3

Now as we know that

V = V_1 + V_2

= 19.91 cm^3 + 50 cm^3

= 69.91 cm^3

Now the weight of dispacement of water is

= 69.91 g

Therefore the apparent weight is

= 225 + 25 - 69.91 g

= 180.1 g