An astronaut has landed on an asteroid and conducts an experiment to determine the acceleration of gravity on that asteroid. He uses a simple pendulum that has a period of oscillation of 2.00 s on Earth and finds that on the asteroid the period is 11.3 s. What is the acceleration of gravity on that asteroid

g' = 0.31 m/s²

Explanation:

First we need to find the length of pendulum, by using the formula of the time period of pendulum:

T = 2π√(L/g)

L = T²g/4π²

where,

L = Length of Pendulum = ?

T = Time Period of Pendulum on Earth = 2 s

g = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

L = (2 s)²(9.8 m/s²)/4π²

L = 0.99 m

Now, we use the formula on asteroid:

T' = 2π√(L/g')

where,

T' = Time Period on Asteroid = 11.3 s

g' = acceleration due to gravity on asteroid = ?

Therefore,

11.3 s = 2π √(0.99 m/g')

(11.3 s)² = 4π²(0.99 m/g')

g' = 39.2 m/(11.3 s)²

g' = 0.31 m/s²

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i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles