Please HELP A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the radius of the circular orbit. Determine the speed of the satellite. Determine the period of the orbit.

Given that,

Mass of satellite = 500 kg

Gravitational force = 3000 N

We need to calculate the radius of the circular orbit

Using formula of gravitational force

Where, G = gravitational constant

R = radius of earth

h = radius of the circular orbit

M = mass of earth

m = mass of satellite

Put the value into the formula

(II). We need to calculate the speed of the satellite

Using formula of velocity

Put the value into the formula

(III). We need to calculate the period of the orbit

Using formula of  time period

Put the value into the formula

Hence, (I). The radius of the circular orbit is

(II). The speed of the satellite is 8.8 km/s.

(III). The period of the orbit is 1.00 hr.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft