a beam of 1mev electrons strike a thick target. for a beam current of 100 microampere, find the power dissipated in the target

power dissipated in the target is 100 W

Explanation:

given data

electrons = 1 mev = eV

1 eV = 1.6 × J

current =  100 microampere = 100 × A

solution

when energy of beam strike with 1 MeV so energy of electron is

E = e × v   ...................1

e is charge of electron and v is voltage

so put here value and we get voltage

v = 1 ÷ 1.6 ×

v =   volt

so power dissipated in target

P = voltage × current   ..............2

put here value

P =    × 100 ×

P = 100 W

so power dissipated in the target is 100 W

the force on the thing and the distance the force moves the thing

c. magnitude and direction