A proton of mass and a charge of is moving through vacuum at a constant velocity of 10000 directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. Required:
How far (in meters) will the proton have been deflected towards the south by the time it exits the region of uniform electric field.

Complete Question

A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E = 3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the time it exits the region of uniform electric field. You may neglect the effects of friction and gravity, and assume that the electric field is zero outside the specified region. Answer is to be in units of meters

Explanation:

From the question we are told that

    The  mass of the proton is  

    The charge of on the proton is

      The speed of the proton is  

     The magnitude of the electric field is  

       The width covered by the electric field          

Generally the acceleration of the proton due to the electric toward the south  (at the point where the force on the proton is equal to the electric force due to the electric field) is  mathematically represented as

Substituting values

Generally the time it will take the proton to cross the electric field is  mathematically represented as

Substituting values

Generally the the distance covered by the proton toward the south is  

   Here  u = 0  m/s  this  because before the proton entered the electric field region the it velocity towards the south is  zero

     So

Substituting values

so easy. just google the electromagnetic waves and it’ll pop up.