An object moving at a speedof 20 m/s loses its speed by 3m/s. How far it travel before it stops?

Distance travel (s) = 67 m (Approx)

Explanation:

Given:

Initial speed (u) = 20 m/s

Final speed (v) = 0 m/s

Acceleration (a) = (-3 m/s²)

Find:

Distance travel (s)

Computation:

v² = u² + 2(a)(s)

0² = 20² + 2(-3)(s)

0 = 400 - 6 s

6 s = 400

S = 66.6667 meter

Distance travel (s) = 67 m (Approx)

answer: good job it's all correct !

explanation:

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