2. A 60 W filament lamp is powered by the 240 V mains electricity supply. The lamp is switched on.
(a) Calculate:
(1) the current in the lamp
current =
[2]
(ii) the resistance of the lamp.
resistance =
[2]

I(current)=0.25A

R (resistance)=960ohms

Explanation:

1.)

P=60W

V=240V

I=?

Power= Current× Potential difference

P=IV

substitute 60 for P and 240 for V

60=I×240

I=60÷240

I=0.25A

Therefore, I=0.25A

2.) V=IR

Substitute 240 for V and 0.25 for I

240=0.25×R

R=240÷0.25

R=960W

Therefore, R=960W

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas

answer is slate

hope this