A spinning top initially spins at 16rad/s but slows down to 12rad/s in 18s, due to friction. If the rotational inertia of the top is 0.0004kg. m2, by how much the angular momentum of the top changes?

The  change  in angular momentum is

Explanation:

From the question we are told that

      The initial angular velocity of the spinning top is  

      The angular velocity after it slow down is  

      The time  for it to slow down is  

       The rotational inertia due to friction is  

 Generally the change in the angular momentum is  mathematically represented as  

substituting values  

cant without the picture! ?

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg