Physics, 14.07.2020 23:01 rileywjones0725

Four particles enter a region of uniform magnetic field with velocities perpendicular to magnetic field lines. The particles have the following masses and charges: 1 : charge q; velocity v and mass m
2: charge 29 velocity 2v and mass 2m
3: charge q: velocity 3v, mass m/2
4: charge 2q: velocity 30, mass 2m
Rank the radii of theirs paths for these particles, largest to smallest

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Answer from: doll1234

r4 > r2 > r3 > r1

Explanation:

correction of the statement:

The particles have the following masses and charges:

1 : charge q; velocity v and mass m

2: charge 2q velocity 2v and mass 2m

3: charge q: velocity 3v, mass m/2

4: charge 2q: velocity 3v, mass 2m

In order to calculate the radius of the trajectories of the four particles, you use the following formula for the radius of the trajectory of a particle in a perpendicular and constant magnetic field:

$r=\frac{mv}{qB}$ (1)

m: mass of the particle

v: speed of the particle

q: charge

B: magnitude of the magnetic field

Then, in comparison with the equation (1), you obtain for each case:

1 : charge q; velocity v and mass m

$r_1=\frac{mv}{qB}$ = r

2: charge 2q velocity 2v and mass 2m

$r_2=\frac{(2m)(2v)}{(2q)B}=2\frac{mv}{qB}=2r$

3: charge q: velocity 3v, mass m/2

$r_3=\frac{(m/2)(3v)}{qB}=\frac{3}{2}\frac{mv}{qB}=\frac{3}{2}r$

4: charge 2q: velocity 3v, mass 2m

$r_4=\frac{(3v)(2m)}{(2q)B}=3\frac{mv}{qB}=3r$

By the previous results you can conclude:

r4 > r2 > r3 > r1

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

there are no contact forces mentioned on the list of choices that you've provided.

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Four particles enter a region of uniform magnetic field with velocities perpendicular to magnetic fi...