A small charged bead has a mass of 3.6 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is released, it accelerates upward with an acceleration of 24 m/s^2. What is the charge on the bead?

The charge on the bead is  

Explanation:

From the question we are told that

     The  mass of the bead is  

      The  magnitude of the electric field is  

       The  acceleration of the bead is  

Generally,  the  electric force on the bead is  mathematically represented as  

Where q is the charge on the bead

   Now the gravitational force opposing the upward movement of the bead is  mathematically represented as

Generally the net force on the bead is  mathematically represented as

=>    

Now substituting values

chemical properties of thing

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2