World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15m/s2. Part A How much horizontal force F must a sprinter of mass 47 kg exert on the starting blocks to produce this acceleration

The horizontal force the sprinter exerts on the starting blocks is 705 N

Explanation:

Given;

mass of the sprinter, m = 47 kg

magnitude of the his horizontal acceleration, aₓ = 15 m/s²

The horizontal force the sprinter exerts on the starting blocks to produce this acceleration, is calculated by applying Newton's second law of motion.

∑Fₓ = maₓ

∑Fₓ = 47 x 15

∑Fₓ = 705 N

Therefore, the horizontal force the sprinter exerts on the starting blocks is 705 N

15.3 cos 65 degrees trig

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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