A 16.0-m uniform ladder weighing 520 N rests against a frictionless wall. The ladder makes a 65.0° angle with the horizontal. (a) Find the horizontal and vertical forces the ground exerts on the base of the ladder when an 850-N firefighter has climbed 4.20 m along the ladder from the bottom. Horizontal Force Magnitude = Direction = Vertical Force Magnitude = Direction =
(b) If the ladder is just on the verge of slipping when the firefighter is 9.40 m from the bottom, what is the coefficient of static friction between ladder and ground?

we can conclude that the component of the horizontal force and vertical force are 225.28 N and 1370 N respectively.

Coefficient of static friction = 0.26

Explanation:

Given that:

length of the ladder = 16.0 m

weight of the ladder = 520 N

angle θ = 65.0°

(a) We are to find the horizontal and vertical forces the ground exerts on the base of the ladder when an :

Force = 850 N

distance of the climber from the base of the ladder = 4.20 m

The diagrammatic illustration representing what the given information entails can be seen from the attached file below.

Let consider the Ladder being at point A with the horizontal layer of the ground.

From the whole system; the condition for the equilibrium at the point A can be computed as :

where ;

w =mg

Therefore; we can conclude that the component of the horizontal force and vertical force are 225.28 N and 1370 N respectively.

(b) If the ladder is just on the verge of slipping when the firefighter is 9.40 m from the bottom, what is the coefficient of static friction between ladder and ground?

the coefficient of static friction between ladder and ground when the firefighter is 9.40 m from the bottom can be calculated as:

Therefore; the coefficient of the static friction is;

 = 0.26

Coefficient of static friction = 0.26

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.