I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block and it oscillates with a period of 0.13 s. What is the amplitude of oscillation

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

Now, determine the amplitude of oscillation, A;

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

Therefore, the amplitude of the oscillation is 2.82 cm

the inner core.

good luck: )

klicker

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