A small segment of a string under tension with a force of Fin which a pulse moves with a speed of v and show how one arrives at equation (1). Show all the details of your work.
2. Starting with the vertical position equation of a wave shown here,
y(x, t) = A sin(kx - wt)
Calculate the vertical position y in [cm], vertical speed Vy in [m/s] and vertical acceleration ay in [m/s] of the wave that the wave driver generated at x = 15 cm and at time t = 3 s during trial 5 of this experiment. Assume that A = 2 cm. The other values in the equation can be calculated from the experimental data. Remember to differentiate the above equation to get the expressions for Vy and ay.
y = 1.447 cm,
V = -4.25 m/s
a = -1372 m/s2
v=√Ft/u
Trial 225.00 Ls = cm Total string length m (e) 250 300 f3 (Hz) 36.1 39.7 43.0 L= 160.50 cm Active length mos = 3.70 Total string mass 350 400 450 500 550 49.0 51.6 mob 50.00 Mass of hanger 0.0164 U= kg/m 600 650 700 Linear density 61.3 | Trial 3 0 4 m (kg) 0.250 0.300 .350 0.400 0.450 0.500 0.550 0.600 0.650 0.700 4.04 4.15 f(Hz) f2 (Hz) 3.47 12.04 3.64 13.25 3.7914.36 3.92 15.37 16.32 17.22 4.25 18.06 18.92 4.43 19.62 4.52 20.43 4.35 10