In short-track speed skating, the track has straight sections and semi-circles 16 m in diameter. Assume that a 66 kg skater goes around the turn at a constant 12 m/s. A. What is the horizontal force on the skater?
B. What is the ratio of this force to the skater's weight?

a. 1,188 N

b. 1.836

Explanation:

The computation is shown below:

a. For horizontal force, first we need to find out the circular path radius which is shown below:

As we know that

= 8m

Now the horizontal force is

where,

m = 66 kg

v = 12 m/s

and r = 8 m

Now placing these values to the above formula

So, the horizontal force is

= 1,188 N

b. Now the ratio of force to the weight of skater is

= 1.836

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.