A straight wire carrying a current of 7.2 A has a field of 8.9 10–3 T at right angles to it. What length of wire in the field will experience a force of 2.1 N? 2.6 10–3 m 3.1 10–1 m 1.3 10–1 m 3.3 101 m

33.18m

Explanation:

the length is 3.3 x 10^1m

3.3x10^1m

Explanation:

F=LIBsinθ

Force F= 2.1N

Length L = unknown

Current I= 7.2A

Magnetic field B = 8.9x10^-3

sinθ = sin90° = 1 (because the field is at right angles to the wire)

2.1 = L (7.2)(8.9x10^-3)(1)

L = 32.77m

= 3.3x10^1m

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

where are the vectors ?