Two point charges are separated by a distance d. The first has a charge of +2e, and the second has a charge of +3 e. How does the electric potential
energy of the +2e charge change if it is moved to a new position, so that it is
separated from the second charge by a distance of 2d?
kch192
(PE = k = 9.00 x 10°Nom? IC?)

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j

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