Please help. Will give brainliest. 20 points.

12.64 m

Explanation:

Recall that the formulas for kinetic & poteintial energy are:

kinetic energy = (1/2) m v²

potential energy = m g h

where m = mass of the baseball,

g = acceleration due to gravity (i.e 9.81 m/s²)

v = initial velocity = 56.7 km/h = 15.75 m/s

h = height (we are asked to find this)

For a baseball to come to a complete stop when thrown straight up and neglecting air resistance. By the conservation of energy, we can say that kinetic energy is entirely transformed into potential energy, i.e

kinetic energy = potential energy

(1/2) m v² = m g h   (m cancels out)

(1/2) v² = g h  (rearranging)

h = (1/2) v² /g

Given that the initial velocity, v = 56.7 km/h = 15.75 m/s

substituting this into our equation:

h = (1/2) v² /g

h = (1/2) (15.75)² /9.81

h = 12.64 m

12.7 m

Explanation:

Given:

v₀ = 56.7 km/h = 15.75 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (15.75 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 12.7 m

he kicked it 10 feet straight up into the air? i think this works.

measure their densities same density, same sub