You are launching a 2 kg potato out of a potato cannon. The cannon is 1.7 m long and is aimed 35 degrees above the horizontal. It exerts a 40 N force on the potato. What is the kinetic energy (in J) of the potato as it leaves the muzzle of the potato cannon?

Explanation:

work done by force exerted by canon = force x displacement

= 40 x 1.7 =  68 N

This energy would have been added to the potato .

Increase in potential energy of potato = mgh

= mg sin 35 x 1.7  = 2 x 9.8 x sin 35 x 1.7 = 19.11 J

Increase in kinetic energy = 68 - 19.11

= 48.89 J

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

battery with hi vtge high val resist in series