A car engine burns gas at 495 K and exhausts to the air at 293 K. What is the highest possible efficiency it could have? (NO UNIT)

59.19%

Explanation:

Step 1:

Data obtained from the question. This include the following:

Input temperature = 495 K.

Output temperature = 293 K.

Efficiency =..?

Step 2:

Determination of the efficiency of the engine.

Efficiency is simply defined as the ratio of output to input times 100. Mathematically, it is expressed as:

Efficiency = output /input x 100

With the above formula, we can calculate the efficiency of the engine as follow:

Input temperature = 495 K.

Output temperature = 293 K.

Efficiency =..?

Efficiency = output /input x 100

Efficiency = 293/495 x 100

Efficiency = 59.19%

Therefore, the efficiency of the engine is 59.19%

which statement about this sum is true? −245+2.7

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~