To maximize the percentage of the power from the emf of a battery that is delivered to a device external to the battery, what should the internal resistance of the battery be?

the internal resistance of the battery be minimized

Explanation:

Because from

P= I²R+I²r

The amount of emf of battery delivered to the external load depends on internal resistance r such that the smaller the r the higher the emf

your answer is, orbit around the nucleus

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j