A charged particle is moving perpendicular to a magnetic field in a circle with a radius r. An identical charge particle enters the field, with v prependicular to B, but with a higher speed than the first particle. Compared with the radius of the circle for the first particle, the radius of the circular path of the second particle is

The second particle will move through the field with a radius greater that the radius of the first particle

Explanation:

For a charged particle, the force on the particle is given as

also recall that work is force times the distance traveled

work = F x d

so, the work on the particle = F x d,

where the distance traveled by the particle in one revolution =

Work on a particle = 2πrF =

This work is proportional to the energy of the particle.

And the work is also proportional to the radius of travel of the particles.

Since the second particle has a bigger speed v, when compared to the speed of the first particle, then, the the second particle has more energy, and thus will move through the field with a radius greater that the radius of the first particle.

33: i think it’s b

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..