The resistance of a 0.29 m long piece of wire is measured to be 0.31 Ohms. The wire has a cross-sectional area of 0.003 m2. What is the resistivity of the wire?

3.21×10⁻³ Ωm

Explanation:

Applying,

R = Lρ/A Equation 1

Where R = Resistance of the wire, L = Length of the wire, ρ = Resistivity of the wire, A = cross sectional area of the wire.

Make ρ the subject of the equation

ρ = RA/L Equation 2

Given: R = 0.31 Ohms, A = 0.003 m², L = 0.29 m

Substitute into equation 2.

ρ = 0.31(0.003)/0.29

ρ  = 3.21×10⁻³ Ωm

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

a. carbon monoxide from car exhaust

b.particulate matter, such as soot

c.water vapor from a factory smokestack

d.acid rain

these are the answer choices im on that question right now