A flat loop of wire consisting of a single turn of cross-sectional area 8.20 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 2.60 T in 1.02 s. What is the resulting induced current if the loop has a resistance of 2.70

The  induced current is

Explanation:

From the question we are told that  

    The number of turns is  

     The  cross-sectional area is  

    The  initial magnetic field is  

     The  magnetic field at time =  1.02 s  is  

     The  resistance is  

The  induced emf is mathematically represented as

The  negative sign tells us that the induced emf is moving opposite to the change in magnetic flux

      Here   is the change in magnetic flux which is mathematically represented as

Where  dB  is the change in magnetic field which is mathematically represented as

substituting values

Thus  

So  

The  induced current i mathematically represented as

  substituting values

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