An evacuated tube uses an accelerating voltage of 50 kV to accelerate electrons to hit a copper plate and produce X-rays. Non-relativistically, what would be the maximum speed (in m/s) of these electrons

Explanation:

Accelerating voltage = 50 x 10³ V

energy created = q V where q is charge on electron and V is accelerating potential

So qV = 1/2 m v² , m is mass of electron and v is velocity

Putting values

1.6 x 10⁻¹⁹ x 50 x 10³ = 1/2 x 9.1 x 10⁻³¹ x v²

v² = 175.8 x 10¹⁴

v = 13.25 x 10⁷ m /s

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

where is the circuit diagram ?