A submarine heads toward a port, which broadcasts a signal at 175 MHz. If the submarine heads toward the port at 46 m/s, what change in frequency does the submarine observe in the port's signal

Δf = 0.00003 MHz = 30 Hz

Explanation:

The apparent frequency due to the motion of receiver towards the source is given by Doppler's effect, while the source is stationary. Therefore, the formula is given as follows:

where,

f = apparent frequency

c = speed of light = 3 x 10⁸ m/s

v₀ = velocity of observer = 46 m/s

f₀ = Original Frequency = 175 MHz = 175 x 10⁶ Hz

Therefore,

f = 175.00003 MHz

Therefore, the change in frequency is:

Δf = f - f₀

Δf = 175.00003 MHz - 175 MHz

Δf = 0.00003 MHz = 30 Hz

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)