A flat loop of wire consisting of a single turn of cross-sectional area 8.60 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 2.40 T in 1.02 s. What is the resulting induced current if the loop has a resistance of 2.80

The  induced current is

Explanation:

From the question we are told that

     The cross-sectional area is  

     The initial value of magnetic field is  

     The  value of magnetic field  at  time  t     is  

     The number of turns  is  N  =  1  

     The  time taken is   =  1.02 \ s  

       The resistance of the loop is  

Generally the induced emf is mathematically represented as

Where   is the change n the magnetic flux which is mathematically represented as

Where is the change in magnetic field which is mathematically represented as  

substituting values  

So  

So  

     Here the negative only indicates that the emf is acting in opposite direction of the motion producing it so the magnitude of the emf is  

Now the induced current is evaluated as follows

substituting values  

there are no contact forces mentioned on the list of choices that you've provided.

at right angles to each other