Help me on this one please, I need it, I beg of you

b,

a, c, and d,

e and f

Explanation:

The total translational kinetic energy is the equal to the number of molecules times the average translational kinetic energy per molecule.

KE = N <KE>

The average kinetic energy for an ideal gas is:

<KE> = 3/2 KT

where K is the Boltzmann constant.

Therefore:

KE = 3/2 KNT

The number of molecules and temperatures of the six gases were:

a) N, T₀

b) N, 2T₀

c) N, T₀

d) N/2, 2T₀

e) N/2, T₀

f) N/2, T₀

If we say KE₀ = 3/2 KNT₀, then the total kinetic energy of each gas is:

a) KE₀

b) 2KE₀

c) KE₀

d) KE₀

e) KE₀/2

f) KE₀/2

he . if i may ask what i your question exactly?

explanation:

lol

explanation: