A 5000 kg mass rocket “breaks the engine” when it is 100 m high and climbing at a speed of 75 m / s. Calculate: 1) The maximum height it will reach
2) The speed with which it will hit the ground after the fall.

1:281.25m

2:75m/s

Explanation:

using the equation

at maximum height v is zero so using that you can make s the subject of the formula

so substitute the velocity 75 and the constant g-10m/s^2

as for the returning velocity we say displacement is zero since you go and come back the same distance

so

u is the initial speed in this case it's positive since going in the direction of gravity

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2