A rifle shoots a 7.00 gram bullet at 285 meters per second over a level field at a 20.0 gram soda can resting on a 1.25 meter post. If the bullet pierces the can right through its center and exits at 245 meters per second (continuing in the same direction as it was fired), where will the can land on the ground?

B) as the temperature increases, the kinetic energy of the particles increases.|-/

B) raising the temperature and reducing the volume of the gas.|-/ 

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.

The object needs to be bigger than you, or (most people would say) you’d be attracting it. no matter how small an object is, if it has mass, it has gravity.