7. An object accelerates at 10 m/s2 for 3 seconds. If its speed after the end of the acceleration is 65 m/s, what is its speed before the acceleration?

Explanation:

So after one second, the acceleration of the ball is 9.8 m/s² and its velocity is 9.8 m/s. When you throw the ball upward, that acceleration is still 9.8 m/s².

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft