Given vector A with rightwards harpoon with barb upwards on top has a magnitude of 5 meters directed 35 degrees above the positive x-axis, and vector B with rightwards harpoon with barb upwards on top has a magnitude of 8 meters directed 70 degrees above the positive x-axis, calculate A with rightwards harpoon with barb upwards on top times B with rightwards harpoon with barb upwards on top . A. 32.8 B. 13 C. 22.9 D. 40

Hello how was your day? ? i hope it was good

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero. 

D. a  bar magnet with its south pole on the left