A green light is submerged 2.70 m beneath the surface of a liquid with an index of refraction 1.31. What is the radius of the circle from which light escapes from the liquid into the air above the surface

The radius is  

Explanation:

From the question we are told that

        The  distance  beneath the liquid  is  

        The refractive index of the liquid is  

Now the critical value is mathematically represented as

substituting values

Using SOHCAHTOA rule we have that

=>    

substituting values  

the bal will not change its velocity.