A 30-µF capacitor is charged to an unknown potential V and then connected across an initially uncharged 10-uF capacitor. If the final potential difference across the .10-µF capacitor is 20 V, determine V

The unknown potential across the 30-µF capacitor is 6.67 V.

The given parameters;

Since the potential difference between the two capacitors are different, the two capacitors are in series connection.

In series circuit arrangement, the quantity of charge flowing in each capacitor is the same.

The potential difference are different and the total potential is given as;

Thus, the unknown potential across the 30-µF capacitor is 6.67 V.

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V = 26.6 volts

Explanation:

Let Initial Potential Difference be V.

Charge (Q) accumulated in 30 mF Capacitor =

Q = C * V

Q= 30 * V

Now, Common Potential after connecting to uncharged 10mF capacitor in parallel = 20 Volt

Total Charge =Total Capacity * Common Potential

30 * V = ( 30 + 10) * 20

V = 26.6 volts

reserve is the answer