At what altitude the value of ‘g’ would become one fourth (¼)of the surface of the earth?

Explanation:

For acceleration due to gravity g , the expression is

g = GM / R² , where G is gravitational constant M is mass of the earth and R is radius of the earth .

At height h , let the value of it becomes g / 4 , so

g / 4 = GM / ( R + h )²

dividing

4 = [( R+ h)² / R² ]

2 = (R + h) / R

2 = 1 + h / R

h / R = 1

h = R

So at height equal to radius of the earth , acceleration due to gravity becomes 1 /4 of value on the surface of the earth .

this could be newton#'s law of cooling. the cooling curve is exponential