beam of white light goes from air into water at an incident angle of 58.0°. At what angles are the red (660 nm) and blue (470 nm) parts of the light refracted? (Enter your answer to at least one decimal place.) red ° blue °

For red light= 39.7°

Blue light 39.2°

Explanation:

Given that refractive index for red light is 1.33 and that of blue light is 1.342

So angle of refraction for red light will be

Sinစi/ (sinစ2) =( nw)r/ ni

Sin 58° x 1.000293/1.33. =( sinစ2)r

0.64= sinစ2r

Theta2r = 39.7°

For blue light

Sinစi/ (sinစ2) =( nw)b/ ni

Sin 58° x 1.000293/1.342 =( sinစ2)b

0.632= sinစ2r

Theta2b= 39.19°

(75°f − 32) × 5/9 = 23.889°c

increases it