Using the Bohr model what is the radius of the electron orbit in the Hydrogen atom when the electron is in the n = 10 state?

 r₁₀ = 52.9 nm

Explanation:

In Bohr's model of the hydrogen atom, the radius of the orbitals can be written as a function of the radius of the first orbit

               rₙ = n² a₀

where ao is 0.0529 nm and is the radius of the ground state of the atom

the radius for the excited state with n = 10

        r₁₀= 10² a₀

        r₁₀ = 100 a₀

        r₁₀ = 52.9 nm