An ideal gas is at a temperature of 320 K. What is the average translational kinetic energy of one of its molecules

6.624 x 10^-21 J

Explanation:

The temperature of the ideal gas = 320 K

The average translational energy of an ideal gas is gotten as

=

where

 is the average translational energy of the molecules

= Boltzmann constant = 1.38 × 10^-23 m^2 kg s^-2 K^-1

T is the temperature of the gas = 320 K

substituting value, we have

= = 6.624 x 10^-21 J

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