A giant armadillo moving northward with a constant acceleration covers the distance between two points 60 m apart in 6 seconds. Its velocity as it passes the second point is 15m/s.

 a = 1.66 m /s²

Explanation:

This is a kinematics exercise

       v = v₀ + a t

        x = v₀ t + ½ a t²

we solve for the initial velocity in the first equation and substitute in the second

       v₀ = v - at

        x = (v- at) t + ½ a t²

        x = vt - a t² + ½ a t²

        x = v t - ½ a t²

we seek acceleration

       a = (v t -x) 2 / t²

let's calculate

        a = (15 6 - 60) 2/6²

        a = 1.66 m /s²

found in the nucleus

has mass of one amu

the answer is a. at the equator