The homogeneous beam of mass 5 kg indicated in the figure is in equilibrium and supported at points A and B. Calculate the reactions at the supports.

Explanation:

Sum of moments about point A:

∑τ = Iα

-mg (L/2) + Rb x = 0

-(5 kg) (10 m/s²) (0.75 m) + Rb (0.70 m) = 0

Rb = 53.6 N

Sum of forces in the y direction:

∑F = ma

Ra + Rb − mg = 0

Ra = mg − Rb

Ra = (5 kg) (10 m/s²) − 53.6 N

Ra = -3.6 N

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