Light of wavelength 500 nm illuminates a round 0.50-mm-diameter hole. A screen is placed 6.0 m past the slit. What is the width of the central bright circle on the screen

14.64*10^-3 m

Explanation:

given that

Length of the wavelength, λ = 500*10^-9 m

Diameter of the hole, D = 0.5 mm

length of the slit, L = 6 m

W = 2.44 λL / D, where

W = width of the screen in m

λ = wavelength of the light in nm

L = length of the slit in m

D = diameter of the hole in m

on substituting the values, we have

W = (2.44 * 500*10^-9 * 6) / 0.5*10^-3

W = 7.32*10^-6 / 0.5*10^-3

W = 0.01464 mm

or also, 14.64*10^-3 m

it about 600 mph from what i calculated

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)