The temperature of a plastic cube is monitored while the cube is pushed 8.6 m across a floor at constant speed by a horizontal force of 19 N. The monitoring reveals that the thermal energy of the cube increases by 120 J. What is the increase in the thermal energy of the floor along which the cube slides

43.4J

Explanation:

We know that

Work done = total heat energy

But work done is force x distance

=> F = 19 x8.6 = 163.4 J

So the total heat. Will be Heat of cube + heat of floor = 163.4J

So that heat of floor will now be

floor = 163.4 J - 120 J = 43.4 Joules

Explanation:

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