Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of the system by a factor of

The frequency changes by a factor of  0.27.

Explanation:

The frequency of an object with mass m attached to a spring is given as

=

where is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

=

simplifying, we have

=

=

if we divide this final frequency by the original frequency, we'll have

==>  ÷  

==>  x  

==> 1/3.742 = 0.27

continuous conducting path for current, power supply

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures