Una lente forma una imagen de un objeto, el cual está a 16.0 cm de la lente. La imagen está a 12.0 cm de la lente del mismo lado que el objeto. a) ¿Cuál es la distancia focal de la lente?¿esta es convergente o divergente? b) Si el objeto tiene 8.50 mm de altura, ¿cuál será la altura de la imagen? ¿es derecha o invertida?

The focal length of the lens is -6.85 cm.

The lens is diverging lens.

The height of the image is 6.4 mm.

Explanation:

Given that,

Object distance = 16.0 cm

Image distance = 12.0 cm

Height of object = 8.50 mm

We need to calculate the focal length of the lens

Using formula of lens

Where, v = image distance

u = object distance

Put the value into the formula

Focal length is negative so the lens will be diverging lens.

We need to calculate the height of the image

Using formula of magnification

Put the value into the formula

Hence, The focal length of the lens is -6.85 cm.

The lens is diverging lens.

The height of the image is 6.4 mm and straight.

what type of charge does it have? negative