If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial acceleration of each of them. aelectron = nothing m/s2

The acceleration of the proton is 2.823 x 10¹⁷ m/s²

The acceleration of the electron is 5.175 x 10²⁰ m/s²

Explanation:

Given;

distance between the electron and proton, r = 7 x 10⁻¹⁰ m

mass of proton, = 1.67 x 10⁻²⁷ kg

mass of electron, = 9.11 x 10⁻³¹ kg

The attractive force between the two charges is given by Coulomb's law;

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/c²

Acceleration of proton is given by;

F = ma

Acceleration of the electron is given by;

close lines strong magnet less close weaker

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.