An object of mass 2 kg starts from rest and is allowed to slide down a frictionless incline so that its height changes by 20 m. How fast is the object moving at the bottom of the incline?

a. 10m/s
b. 20m/s
c. 30m/s
d. 40m/s

B

Explanation:

Given that an object of mass 2 kg starts from rest and is allowed to slide down a frictionless incline so that its height changes by 20 m. 

The parameters given from the question are:

Mass M = 2kg

Height h = 20m

Let g = 9.8m/s^2

At the bottom of the incline plane, the object will experience maximum kinetic energy.

From conservative of energy, maximum K.K.E = maximum P.E

Maximum P.E = mgh

Maximum P.E = 2 × 9.8 × 20 = 392 J

But

K.E = 1/2mv^2

Substitute the values of energy and mass into the formula

392 = 1/2 × 2 × V^2

V^2 = 392

V = sqrt( 392 )

V = 19.8 m/s

V = 20 m/s approximately

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day