How many electrons flow through a point in a wire in 7.00 s if there is a constant current of I = 4.35 A?

1.90×10²⁰ Electrons

Explanation:

From the question,

Q = It Equation 1

Where Q = charge flowing through the wire, I = current, t = time

Given: I = 4.35 A, t = 7.00 s

Substitute these values into equation 1

Q = 4.35(7.00)

Q = 30.45 C.

But,

1 electron contains 1.6×10⁻¹⁹ C

therefore,

30.45 C = 30.45/1.6×10⁻¹⁹  electrons

= 1.90×10²⁰ Electrons

b

explanation:

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